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8 February, 08:55

Solve for v.

(v-1) ^2 = 2v^2 - 5v - 17

If can be more than one solution or no solution

+3
Answers (1)
  1. 8 February, 09:04
    0
    (v - 1) ² = 2v² - 5v - 17

    (v - 2) (v - 2) = 2v² - 5v - 17

    v² - 2v - 2v + 4 = 2v² - 5v - 17

    v² - 4v + 4 = 2v² - 5v - 17

    - v² - v²

    -4v + 4 = v² - 5v - 17

    + 5v + 5v

    v + 4 = v² - 17

    + 17 + 17

    v + 21 = v²

    0 = v² + v + 21

    v² + v + 21 = 0

    v = - (1) + / - √ ((1) ² - 4 (1) (21))

    2 (1)

    v = - 1 + / - √ (1 - 84)

    2

    v = - 1 + / - √ (-83)

    2

    v = - 1 + / - 9.11i

    2

    v = - 1 + 4.555i

    v = - 1 + 4.555i v = - 1 - 4.555i

    There is more than one solution.
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