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27 December, 02:35

Solve the quadratic a (^ means to the power of)

1) K^2 - 12k = 0

2) X^2 - 19x = 0

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Answers (1)
  1. 27 December, 02:44
    0
    K^2-12k=0

    k (k-12) = 0

    set to zero

    k=0

    k-12=0

    k=12

    k=0 or 12

    2.

    x^2-19x=0

    x (x-19) = 0

    set to zer o

    x=0

    x-19=0

    x=19

    x=0 or 19

    1. x=0 or 12

    2. x=0 or 19
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