Ask Question
4 October, 20:33

A 13 -pound mixture of coffee that contains both decaffeinated and regular coffee costs $34. The decaffeinated coffee costs $2 per pound, and the regular coffee costs $3 per pound. (a) Let x be the weight of the decaffeinated coffee and y be the weight of the regular coffee. Write a system of equations whose solution gives the amount of each type of coffee in the mixture. (b) Use the method of substitution to solve the system of equations.

+1
Answers (1)
  1. 4 October, 20:51
    0
    Weight of decaf coffee = 5 pounds.

    Weight of regular coffee = 8 pounds.

    Step-by-step explanation:

    (a) Let x be the weight of decaf coffee and y the weight of regular coffee. Then:

    x + y = 13

    2x + 3y = 34

    (b) From the first equation x = 13 - y, so substituting for x in second equation:

    2 (13 - y) + 3y = 34

    26 - 2y + 3y = 34

    y = 34 - 26 = 8.

    Substituting for y in the first equation:

    x + 8 = 13

    x = 5.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 13 -pound mixture of coffee that contains both decaffeinated and regular coffee costs $34. The decaffeinated coffee costs $2 per pound, ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers