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10 August, 05:06

Solve e ^ - x^2 = 0.23

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  1. 10 August, 05:16
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    If e repersents the something of logarithms then

    I memorised e to 16 digits:2.718281828459045 ...

    so that number^2-x^2=0.23

    number squred=aprox 7.38906

    7.38906-x^2=0.23

    subtract 7.38906 forom both sides

    -x^2=-7.15906

    multiply negative

    x^2=7.15906

    squre root

    2.67564=x
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