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22 September, 11:38

How do you solve 12+5x = 18+3x

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Answers (2)
  1. 22 September, 11:43
    0
    x=3

    Step-by-step explanation:

    First, get your variables and constants separated on either side of the =

    Whatever you do to one side, you have to do to the other.

    12 + 5x = 18 + 3x

    subtract 3x from both sides to cancel out the 3x on the right:

    12 + 5x - 3x = 18 + 3x - 3x

    12 + 2x = 18

    subtract 12 from both sides to cancel out the 12 on the left side:

    12 - 12 + 2x = 18 - 12

    now just solve for x

    2x = 6

    divide both sides by 2 to cancel out the 2 on the left side:

    2x / 2 = 6 / 2

    x = 3
  2. 22 September, 11:52
    0
    Answer: x = 3

    Step-by-step explanation:Simplifying

    12 + 5x = 18 + 3x

    Solving

    12 + 5x = 18 + 3x

    Solving for variable 'x'.

    Move all terms containing x to the left, all other terms to the right.

    Add '-3x' to each side of the equation.

    12 + 5x + - 3x = 18 + 3x + - 3x

    Combine like terms: 5x + - 3x = 2x

    12 + 2x = 18 + 3x + - 3x

    Combine like terms: 3x + - 3x = 0

    12 + 2x = 18 + 0

    12 + 2x = 18

    Add '-12' to each side of the equation.

    12 + - 12 + 2x = 18 + - 12

    Combine like terms: 12 + - 12 = 0

    0 + 2x = 18 + - 12

    2x = 18 + - 12

    Combine like terms: 18 + - 12 = 6

    2x = 6

    Divide each side by '2'.

    x = 3

    Simplifying

    x = 3
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