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16 September, 15:27

Find dy/dx by implicit differentiation.

x^2/x+y=y^2+7

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  1. 16 September, 15:37
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    dy/dx = (2x - y² - 7) / (2xy + 3y² + 7)

    Step-by-step explanation:

    x² / (x + y) = y² + 7

    x² = (x + y) (y² + 7)

    Take derivative of both sides with respect to x. Use power rule, product rule, and chain rule.

    2x = (x + y) (2y dy/dx) + (y² + 7) (1 + dy/dx)

    Simplify.

    2x = (2xy + 2y²) dy/dx + y² + y² dy/dx + 7 + 7 dy/dx

    2x = (2xy + 3y² + 7) dy/dx + y² + 7

    2x - y² - 7 = (2xy + 3y² + 7) dy/dx

    dy/dx = (2x - y² - 7) / (2xy + 3y² + 7)
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