Ask Question
23 October, 16:14

The area of a rectangle is 81x^10y^2. If the length of the rectangle is 3x^6y^-4, find the width

+2
Answers (1)
  1. 23 October, 16:28
    0
    width = (27x⁴) (10y⁶)

    Step-by-step explanation:

    Multiplying numbers will multiply their coefficient. For 3x, 3 must multiply with another number to get 81. That number is 27, so 3x (27) = (3⋅27) x = 81x.

    Now you need the power.

    Multiplying numbers with the same base will add up their exponent. I got x⁶ but need to get to x¹⁰.

    Just multiply it by x⁴ so that you get (x⁶) (x⁴) = x⁶⁺⁴ = x¹⁰.

    Do the same for y.

    A = LW

    (81x¹⁰) (10y²) = (3x⁶) (y⁻⁴) (W)

    (81x¹⁰) (10y²) = (3x⁶) (y⁻⁴) (27x⁴) (10y⁶)

    (81x¹⁰) (10y²) = (3x⁶) (27x⁴) (y⁻⁴) (10y⁶)

    (81x¹⁰) (10y²) = (3⋅27x⁶⁺⁴) (y⋅10⁻⁴⁺⁶)

    (81x¹⁰) (10y²) = (81x¹⁰) (10y²)

    width = (27x⁴) (10y⁶)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The area of a rectangle is 81x^10y^2. If the length of the rectangle is 3x^6y^-4, find the width ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers