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20 August, 04:08

F (x) = 3x^2-18x+27

can you solve this?

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Answers (2)
  1. 20 August, 04:16
    0
    I can factor it

    3x^2 - 18x + 27

    = 3 (x^2 - 6x + 9

    = 3 (x - 3) ^2

    If we equate this to 0 we can solve for x:-

    3 (x - 3) ^2 = 0

    so x - 3 = 0

    and x = 3 (duplicity 2)
  2. 20 August, 04:21
    0
    What do you mean by "solve this?" Until you set f (x) = to some constant number, you don't have an equation and thus can't expect to find solutions.

    Why don't we take 3x^2-18x+27 and set it = to 0, and only then try to solve this equation?

    3x^2-18x+27 = 0. Dividing both sides by 3, we get x^2 - 6x + 9 = 0, which can be factored as

    (x-3) ^2 = 0. Taking the sqrt of both sides, we get x-3 = 0. Actually, there are 2 roots: 3 and 3. Again, this statement is true only if we set 3x^2-18x+27 = to 0.
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