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18 April, 17:54

The sum of four consecutive integers is 418. Find them.

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  1. 18 April, 18:23
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    Answer: 103, 104, 105, and 106

    Step-by-step explanation: This problem states that the sum of 4 consecutive integers is 418 and it asks us to find the integers.

    First represent your 4 consecutive integers as follows.

    X ⇒ first integer

    X + 1 ⇒ second integer

    X + 2 ⇒ third integer

    X + 3 ⇒ fourth integer

    Since their sum is 418, our equation reads

    x + (x + 1) + (x + 2) + (x + 3) = 418.

    Simplifying on the left side we get 4x + 6 = 418.

    Now we can subtract 6 from both sides of the equation and we have

    4x = 412.

    Now just divide both sides by 4 and we find that x = 103.

    Finally, make sure you list all your answers.

    If x is 103, then x + 1 is 104, x + 2 is 105, and x + 3 is 106

    Therefore, our 3 consecutive integers are 103, 104, 105, and 106.
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