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13 September, 21:21

The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both increased by 2, the fraction is now equal to. If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?

A. 5n = 3d and 3n + 6 = 2d + 4

B. 5n = 3d and 4n + 4 = 3d + 6

C. 3n = 5d and 3n + 6 = 2d + 4

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Answers (1)
  1. 13 September, 21:32
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    3/5 = n/d

    3d = 5n

    n + 2 & d + 2

    3/5 = n+2 / d+2

    3 (d+2) = 5 (n+2)

    3d + 6 = 5n + 10 Closest answer would be: B. 5n = 3d & 4n + 4 = 3d + 6
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