The equation of a circle is (x-3) ^2 + (y+8) ^2=36. Relative to the standard equation of a circle (x^2+y^2=r^2), how has this circle been shifted? What is the radius of the circle?

Question

Krish Hood

Mathematics

6 June, 07:21

The equation of a circle is (x-3) ^2 + (y+8) ^2=36. Relative to the standard equation of a circle (x^2+y^2=r^2), how has this circle been shifted? What is the radius of the circle?

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Answers (2)

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Eve Vega · Answer 1

The circle shifts to the right 3 units and down 8 units. It's radius is 6

Asa Grimes · Answer 2

The circle has been shifted 3 units to the right and 8 units down.

The radius of the circle would be square root of 36, which is 6

Radius = 6 units

Translation = 3 units horizontally right, 8 units vertically down