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Find the consecutive integers such that the sum of the first and twice the second is 80 minus three the third.

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  1. 29 May, 04:56
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    Let the integers be a, a+1 and a+2

    from question

    a + 2 (a+1) = 80-3 (a+2)

    a+2a+2 = 80-3a-6

    3a+3a = 72

    a = 72/6 = 12
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