The expected number of free throws is the probability of one free throw (70%) times the number of free throws. 6 * 0.7 = 4.2 so you expect about 4 free throws out of the 6. As you can see in the simulations above, the number of scores were all close to 4.

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Renee Craig

Mathematics

12 January, 07:42

The expected number of free throws is the probability of one free throw (70%) times the number of free throws. 6 * 0.7 = 4.2 so you expect about 4 free throws out of the 6. As you can see in the simulations above, the number of scores were all close to 4.

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Cory Mccarthy · Answer 1

a) Let 0-6 stand for a score and 7-9 stand for a miss. This means 7 numbers that mean score and 3 numbers that mean miss, which gives it a 70% chance. Take 6 of the digits for each of the 5 simulations. 189741 - 3 scores 586463 - 5 scores 856648 - 4 scores 770615 - 4 scores 645468 - 5 scores