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27 July, 04:13

What is the perimeter of a rectangle with the width equal to 45 feet and a length twice as long as the width?

A. 270 feet

B. 180 feet

C. 135 feet

D. 2025 feet

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Answers (2)
  1. 27 July, 04:31
    0
    A) 270 feet two time 45 feet is 90 and 90+90+45+45=270
  2. 27 July, 04:37
    0
    You would do 45*2 to find the length, which would be 90.

    Perimeter is length+length+width+width.

    So it would be 45+45+90+90

    the answer is A. 270
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