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Inchworm
Mathematics
4 July, 20:24
Given a+b=7 and a-b=3, find:
3^a:3^b
+3
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2
)
Cassius Hatfield
4 July, 20:26
0
a = - 2 and b=3
Step-by-step explanation:
Step 1) Solve the first equation for a:
a + 3b = 7
a + 3b - 3b = 7 - 3b
a + 0 = 7 - 3b
a = 7 - 3b
Step 2) Substitute (7 - 3b) for a in a second equation and solve for b:
2a = b - 7 becomes:
2 (7 - 3b) = b-7
(2 multi. 7) - (2 multi. 3b) = b-7
14 - 6b = b - 7
14 + 7 - 6b + 6b = b + 6b = b + 6b - 7 + 7
21 - 0 = 1b + 6b - 0
21 = (1 + 6) b
21 = 7b
21 / 7 = 7b/7
3 = 7b/7
3 = b
b = 3
Step 3) Substitute 3 for b in the solution to the first equation at the end of Step 1 and calculate a:
a = 7 - 3b becomes:
a = 7 - (3 ⋅ 3)
a = 7 - 9
a = - 2
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Julius Washington
4 July, 20:44
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I'm not under standing what you're asking
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