The perimeter of a rectangle is 256 inches. How long are the sides if the length exceeds the width by 16 inches? Mark lets x represent the width of the rectangle and writes the equation 2x + 2 (x + 16) = 256. Solving for x, the width of the rectangle is

Question

Laney Miller

Mathematics

11 October, 11:25

The perimeter of a rectangle is 256 inches. How long are the sides if the length exceeds the width by 16 inches? Mark lets x represent the width of the rectangle and writes the equation 2x + 2 (x + 16) = 256. Solving for x, the width of the rectangle is

+2

Answers (1)

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Mara Horton · Answer 1

2x + 2x + 32 = 256

-32

2x+2x = 224

4x=224

/4

x = 56

lenght = width+16

perimeter = width + width + (width + 16) + (width + 16)

perimeter = x + x + (x+16) + (x+16)

perimeter = 2x + 2 ((x+16)

therefore width = 56

length = 72