Ask Question
2 November, 10:30

a population of muskrats oscillates 33 above and below average during the year, hitting the lowest value in january. the average population starts at 900 muskrats and increases by 7 % each month. find an equation for the population p in terms of the months since january t

+1
Answers (1)
  1. 2 November, 10:42
    0
    P = 867 (1.07) ^t

    Step-by-step explanation:

    The population of muskrats oscillates 33 above and below average during the year, hitting the lowest value in january.

    If the average value = 900 muskrats

    Then the lowest = 900 - 33 = 867

    It increases by 7 % each month

    R = 7%

    equation for the population p in terms of the months since january t will be

    P = Po (1 + R%) ^t

    P = 867 (1 + 0.07) ^t

    P = 867 (1.07) ^t
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “a population of muskrats oscillates 33 above and below average during the year, hitting the lowest value in january. the average population ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers