Fiona recorded the number of miles she biked each day last week as shown below. 4, 7, 4, 10, 5 The mean is given by m = 6. Which equation shows the variance for the number of miles Fiona biked last week? s squared = StartFraction (4 minus 6) squared + (7 minus 6) squared + (4 minus 6) squared + (10 minus 6) squared + (5 minus 6) squared Over 6 EndFraction Sigma = StartRoot StartFraction (4 minus 6) squared + (7 minus 6) squared + (4 minus 6) squared + (10 minus 6) squared + (5 minus 6) squared Over 5 EndFraction EndRoot s = StartRoot StartFraction (4 minus 6) squared + (7 minus 6) squared + (4 minus 6) squared + (10 minus 6) squared + (5 minus 6) squared Over 4 EndFraction EndRoot Sigma squared = StartFraction (4 minus 6) squared + (7 minus 6) squared + (4 minus 6) squared + (10 minus 6) squared + (5 minus 6) squared Over 5 EndFraction

Question

Colten Shields

Mathematics

8 September, 22:47

Fiona recorded the number of miles she biked each day last week as shown below. 4, 7, 4, 10, 5 The mean is given by m = 6. Which equation shows the variance for the number of miles Fiona biked last week? s squared = StartFraction (4 minus 6) squared + (7 minus 6) squared + (4 minus 6) squared + (10 minus 6) squared + (5 minus 6) squared Over 6 EndFraction Sigma = StartRoot StartFraction (4 minus 6) squared + (7 minus 6) squared + (4 minus 6) squared + (10 minus 6) squared + (5 minus 6) squared Over 5 EndFraction EndRoot s = StartRoot StartFraction (4 minus 6) squared + (7 minus 6) squared + (4 minus 6) squared + (10 minus 6) squared + (5 minus 6) squared Over 4 EndFraction EndRoot Sigma squared = StartFraction (4 minus 6) squared + (7 minus 6) squared + (4 minus 6) squared + (10 minus 6) squared + (5 minus 6) squared Over 5 EndFraction

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Answers (1)

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Castaneda · Answer 1

s = [ (4-6) ^2 + (7-6) ^2 + (4-6) ^2 + (10-6) ^2 + (5-6) ^2] / 5

Step-by-step explanation:

Given the dа ta:

Number of miles biked each day:

X = 4, 7, 4, 10, 5

The mean of data:

Mean (m) = (sum of X) / n

Where n is the number of observations or days

m = (4 + 7 + 4 + 10 + 5) / 5

m = 30 / 5

m = 6

The variance of the data (s):

s = [Sum of (x - m) ^2] / n

s = [ (4-6) ^2 + (7-6) ^2 + (4-6) ^2 + (10-6) ^2 + (5-6) ^2] / 5

Where s = variance, m = mean, x = data values