Nola hiked down a trail at a steady rate for 10 minutes. Her change in elevation was - 200 ft. Then she continued to hike down for another 20 minutes at a different rate. Her change in elevation for this part of the hike was - 300 ft. During which portion of did she walk down at a faster rate? Explain your reasoning.

Question

Zackery Sharp

Mathematics

17 November, 03:14

Nola hiked down a trail at a steady rate for 10 minutes. Her change in elevation was - 200 ft. Then she continued to hike down for another 20 minutes at a different rate. Her change in elevation for this part of the hike was - 300 ft. During which portion of did she walk down at a faster rate? Explain your reasoning.

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Bandit · Answer 1

Her first rate was faster. The 10 minutes with a change in elevation of - 200ft.

In order to solve this you need to have the same minutes. In this problem, I just simply took the 10 minutes and the - 200ft and doubled it. Now both rates have 20 minutes. The first rate would have gone - 400ft in 20 minutes while the second rate was only - 300ft in 20 minutes. I hope this wasn't confusing, and I'm willing to explain more.