One more rectangular-shaped piece of metal siding needs to be cut to cover the exterior of a pole barn. The area of the piece is 30 ft². The length is 1 less than 3 times the width. How wide should the metal piece be? Round to the nearest hundredth of a foot.

A.) 3.33 ft

B.) 4.3 ft

C.) 1 ft

D.) 30 ft

Question

Blaze Lloyd

Mathematics

17 December, 21:31

One more rectangular-shaped piece of metal siding needs to be cut to cover the exterior of a pole barn. The area of the piece is 30 ft². The length is 1 less than 3 times the width. How wide should the metal piece be? Round to the nearest hundredth of a foot.

A.) 3.33 ft

B.) 4.3 ft

C.) 1 ft

D.) 30 ft

+3

Answers (1)

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Garrett Douglas · Answer 1

Let w be the width of the rectangle. With this representation, length becomes 3w - 1. The area of the rectangular figure is,

A = L x W

where L and W are length and width, respectively. Substituting the known values,

30 ft² = (3w - 1) (w)

The value of w from the equation is 3.33 ft.

One more rectangular-shaped piece of metal siding needs to be cut to cover the exterior of a pole barn. The area of the piece is 30 ft². The length is 1 less than 3 times the width. How wide should the metal piece be? Round to the nearest hundredth of a foot.A.) 3.33 ftB.) 4.3 ftC.) 1 ftD.) 30 ft