Find the x and y intercepts of f (x) = x^3+2x^2-9x-18

X - Intercept: f (x) = x³ + 2x ² - 9x - 18

0 = x³ + 2x² - 9x - 18

0 = x² (x) + x² (2) - 9 (x) - 9 (2)

0 = x² (x + 2) - 9 (x + 2)

0 = (x² - 9) (x + 2)

0 = (x² - 3x + 3x - 9) (x + 2)

0 = (x (x) - x (3) + 3 (x) - 3 (3)) (x + 2)

0 = (x (x - 3) + 3 (x - 3)) (x + 2)

0 = (x + 3) (x - 3) (x + 2)

x + 3 = 0 or x - 3 = 0 or x + 2 = 0

- 3 - 3 + 3 + 3 - 2 - 2

x = - 3 x = 3 x = - 2

Solution set: {±3, - 2} or {-3, 3, 2}

Y - Intercept: f (x) = x³ + 2x² - 9x - 18

f (x) = (0) ³ + 2 (0) ² - 9 (0) - 18

f (x) = 0 + 2 (0) - 0 - 18

f (x) = 0 + 0 - 18

f (x) = 0 - 18

f (x) = - 18