A box contains 12 transistors, 3 of which are defective. If 3 are selected at random, find the probability?

All are Defective =

None are defective=

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22 October, 02:27

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Aliya Allison · Answer 1

P (all are defective) = (3/12) ^3 = (1/4) ^3 = 1/64

P (none are defective) = (9/12) ^3 = (3/4) ^3 = 27/64

A box contains 12 transistors, 3 of which are defective. If 3 are selected at random, find the probability?All are Defective =None are defective=