Which system of equations can you use to find the roots of the equation? x3 - 10x = x2 - 6 y = x3 - x2 + 10x + 6 y = 0 y = x3 - x2 + 10x y = 6 y = x3 - 10x y = x2 - 6

x3-4x2-10x-12=0 Three solutions were found : x = 6 x = (-2-√-4) / 2=-1-i = - 1.0000-1.0000i x = (-2+√-4) / 2=-1+i = - 1.0000+1.0000i

Step by step solution : Step 1 : Equation at the end of step 1 : (((x3) - 22x2) - 10x) - 12 = 0 Step 2 : Checking for a perfect cube:

2.1 x3-4x2-10x-12 is not a perfect cube

Trying to factor by pulling out:

2.2 Factoring: x3-4x2-10x-12

C

y = x3 - 10x

y = x2 - 6