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31 July, 01:50

What are the solutions of the equation (x + 2) 2 - 2 (x + 2) - 15 = 0? Use u substitution to solve.

x = - 7 and x = 1

x = - 5 and x = 3

x = - 3 and x = 5

x = - 1 and x = 7

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  1. 31 July, 02:06
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    x = - 5 and x = 3

    Working

    (x+2) ^2-2 (x+2) - 15=0

    On expanding;

    x^2+4x+4-2x-19=0

    Simplifying gives:

    x^2+2x-15=0

    This can be expanded to;

    x^2+5x-3x-15=0

    Factoring out;

    x (x+5) - 3 (x+5) = 0

    (x-3) (x+5) = 0

    x=3 or x = - 5
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