12 yellow balls and 9 red balls are placed in an urn. Two balls are then drawn in succession without replacement. What is the probability that the first ball drawn is a red ball if the second ball drawn is yellow? a) 0.8333 b) 0.4500 c) 0.5714 d) 0.4762 e) 0.2593 f) None of the abov

Question

Brennen Gill

Mathematics

13 September, 07:31

12 yellow balls and 9 red balls are placed in an urn. Two balls are then drawn in succession without replacement. What is the probability that the first ball drawn is a red ball if the second ball drawn is yellow? a) 0.8333 b) 0.4500 c) 0.5714 d) 0.4762 e) 0.2593 f) None of the abov

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Jaidyn Pollard · Answer 1

If 21 balls are placed in an urn, 12 being yellow, and 9 being red, the probability that the first ball drawn is a red ball is always 9/21 or approximately 0.4286. This answer is true regardless of what color the second ball is. The answer to this question is f) None of the above.