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24 September, 12:34

What is the vertex form of y = x^2 - 20x + 15

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  1. 24 September, 12:39
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    So your equation is y = x² - 20x + 15. what you'll want to do is complete the square, so take half of 20 and square it. 20/2 = 10. 10² = 100. add 100 to both sides. and simplify x²-20x+100+15 to (x²-10) ²+15. now subtract 100 from both sides to get y alone. this leaves you with y = (x²-10) - 85. that's your vertex form.
  2. 24 September, 12:56
    0
    Given a function:

    y=ax²-bx+c

    The vertex is: (-b/2a, f (-b/2a)

    In this case:

    y=x²-20x+15

    -b/2a=20/2=10

    f (10) = 10²-20 (10) + 15=100-200+15=-85

    Answer: The vertex is (10,-85)

    Given a vertex (h, k), the vertex form is:

    y=a (x-h) ²+k

    In this case:

    (10,-85)

    a=1

    y = (x-10) ²-85

    Answer: y = (x-10) ²-85
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