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21 July, 09:32

If x^2+y^2 = 25 and dy/dt = 6, find dx/dt when y=4

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  1. 21 July, 09:34
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    2x dx/dt + 2y dy/dt = 0

    x dx/dt + y (6) = 0

    dx/dt = - 6y/x

    dx/dt = - 6*4 / x

    dx/dt=-24/x

    also from the given equation x^2 = 25-16=9 or x=3

    using this we get

    dx/dt=-24/3 = - 8
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