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15 June, 13:07

Evaluate Integral: 2sin (2x) from 0, pi/2

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  1. 15 June, 13:08
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    Integral of 2sin (2x) is - cos (2x)

    from 0 to pi/2 (sub pi/2 minus sub 0 for x) and then solve

    = - cos (2*pi/2) - (-cos0)

    = - cos pi + cos 0

    = 1 + 1

    = 2
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