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3x-6y=12

x - 2 0 4

y

Given function : 3x-6y=12.

We are given x : - 2 0 4.

We need to find the values of y's for x=-2, x=0 and x=4.

Plugging x=-2 in the given equation, we get

3 (-2) - 6y=12

-6 - 6y = 12.

Adding 6 on both sides, we get

-6+6 - 6y = 12+6

-6y = 18.

Dividing by - 6 on both sides, we get

y = - 3.

On the same way, plugging x=0.

3 (0) - 6y=12

-6y = 12.

y=-2.

Plugging x=4,

3 (4) - 6y=12

12 - 6y = 12.

Subtracting 12 on both sides.

12-12 - 6y = 12-12

-6y=0

y=0.

Therefore,

x - 2 0 4y - 3 - 2 0