The volume V of an ideal gas varies directly with the temperature T and inversely with the

pressure P. A cylinder contains oxygen at a temperature of 320 degrees Kelvin and a pressure of

25 atmospheres in a volume of 120 liters. Find the pressure if the volume is decreased to 110

liters and the temperature is increased to 335 degrees Kelvin.

Hint: Look at the equation V = k * Then use the initial values to solve for k. Then plug in the

values you know for the second set of values and solve for your unknown.

Question

Carla Marsh

Mathematics

24 February, 22:45

The volume V of an ideal gas varies directly with the temperature T and inversely with the

pressure P. A cylinder contains oxygen at a temperature of 320 degrees Kelvin and a pressure of

25 atmospheres in a volume of 120 liters. Find the pressure if the volume is decreased to 110

liters and the temperature is increased to 335 degrees Kelvin.

Hint: Look at the equation V = k * Then use the initial values to solve for k. Then plug in the

values you know for the second set of values and solve for your unknown.

+3

Answers (1)

Know the Answer?

Bruno Andrade · Answer 1

Pressure=22.55 atmospheres

Step-by-step explanation:

Let

V=volume of the ideal gas

P=pressure

T=temperature

Volume varies directly with temperature and inversely with pressure

V=kT/P

t=320°K

P=25 atmospheres

V=120 liters

V=kT/P

120=k*320/25

120=320k/25

120*25=320k

3000=320k

k=300/320

=9.375

k=9.375

V=110 liters

p=?

t=335°K

V=kT/P

110=9.375*335/p

110=3,140.625/p

110p=3,140.625

P=3,140.625/110

=28.55

P=22.55 atmospheres