Find the minimum value of the parabola y=x^2+x

Step-by-step explanation:

The vertex of the parabola represents the mimimum value. A no calculus method of finding is as follows: Consider y = x^2 + 3x + 1, where a = 1 and b = 3. the x - co-ordinate is equal to - b/2a which equals - 3/2. to find the y co-ordinate: y = (-3/2) ^2 - 3 (3/2) + 1. y = 9/4 - 9/2 + 1. y = - 5/4. The minimum value (-5/4) is found at (-3/2, - 5/4)