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9 February, 19:13

If s (x) = x - 7 and t (x) = 4x2 - x + 3, 4 (x - 7) 2 - x - 7 + 3 4 (x - 7) 2 - (x - 7) + 3 (4x2 - x + 3) - 7 (4x2 - x + 3) (x - 7)

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  1. 9 February, 19:17
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    Answers:

    1) (s o t) (x) = 4x^2-x-4

    2) (t o s) (x) = 4 (x-7) ^2 - (x-7) + 3

    Solution:

    1) (s o t) (x) = s (t (x)) = s (4x^2-x+3) = (4x^2-x+3) - 7=4x^2-x+3-7

    (s o t) (x) = 4x^2-x-4

    2) (t o s) (x) = t (s (x)) = t (x-7) = 4 (x-7) ^2 - (x-7) + 3

    (t o s) (x) = 4 (x-7) ^2 - (x-7) + 3
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