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20 January, 13:10

What is the vertex and axis of symmetry for y=4x^2-12x+9?

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  1. 20 January, 13:15
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    axis of symmetry x=3/2

    vertex (3/2, 0)

    Step-by-step explanation:

    to find the axis of symmetry we use h = - b/2a

    where ax^2 + bx+c

    h = - (-12) / 2 (4)

    h = 12/8

    h = 3/2

    the axis of symmetry is x = 3/2

    the x coordinate of the vertex is h x=3/2

    to find k, the y coordinate of the vertex, substitute x=3/2 into the equation

    y=4x^2-12x+9

    y=4 (3/2) ^2-12 (3/2) + 9

    = 4 (9/4) - 6*3 + 9

    = 9-18+9

    = 0

    the vertex (3/2, 0)
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