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16 August, 01:10

You are dealt two cards without replacement what is the probability the first card is one of 4 twos and second is 4 tens in a deck

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  1. 16 August, 01:28
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    A = drawing a two card

    B = drawing a ten card

    P (A) = 4/52 = 1/13

    P (B|A) = P (A and B) / P (A)

    P (A) * P (B|A) = P (A and B)

    P (A and B) = P (A) * P (B|A)

    P (A and B) = (1/13) * (4/51)

    P (A and B) = 4/663

    P (A and B) = 0.006033

    The answer as a fraction is exactly 4/663

    The answer in decimal form is approximately 0.006033
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