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What is the answer to 52-x²+x=10?

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  1. 11 May, 20:20
    0
    -x2+x+52=10

    Subtract 10 from both sides.

    -x2+x+52-10=10-10

    -x2+x+42=0

    Factor left side of equation.

    (-x-6) (x-7) = 0

    Set factors equal to 0.

    -x-6=0 or x-7=0

    x=-6

    or

    x=7
  2. 11 May, 20:30
    0
    52 - x^2 + x = 10

    52 + x = 10 + x^2

    52 = x^2 - x + 10

    x^2 - x - 42 = 0

    x^2 - 7x + 6x - 42 = 0

    x (x-7) + 6 (x-7) = 0

    (x-7) (x+6) = 0

    x = 7

    x = - 6
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