6w^2-11w-35

I need to factor the problem

Hello:

6w²-11w-35

Δ = b²-4ac a = 6 b = - 11 c = - 35

Δ = (-11) ² - 4 (6) (-35) = 121 + 840 = 961=31²

w1 = (11-31) / 12 = - 20/12 = - 5/3

w2 = (11+31) / 12 = 42/12 = 7/2

6w²-11w-35 = 6 (w-w1) (w-w2) = 6 (w+5/3) (w-7/2)

= 1/2 (6w+10) (2w-7)

6w²-11w-35 = (3w+5) (2w-7)

6w^2 - 21w + 10w - 35

3w (2w - 7) + 5 (2w - 7)

(3w + 5) (2w - 7)

This is the factorised form.