Ask Question
8 May, 20:55

An empty 5 gallon water jug weighs 0.75 lbs. With 3 cups of water inside, the jug weighs 2.25 lbs. What equation models the jug's weight y when it contains x cups of water?

+4
Answers (2)
  1. 8 May, 21:00
    0
    Step-by-step explanation:

    3 cups of water + jug = 2.25 lbs

    jug =.75 lbs

    3 cups of water = 1.5 lbs

    1 cup of water =.5 lbs

    Therefore,

    y =.75 +.5x
  2. 8 May, 21:03
    0
    Answer: jugs weight ⇒ y = 0.75 + 0.5 x

    Step-by-step explanation:

    Hi, to solve this problem we have to analize the information given.

    So:

    Empty jug weight = 0.75 lbs

    jug with 3 cups of water weight = 2.25

    The next step is to subtract the weight of the empty jug to the weight of the jug with 3 cups.

    2.25 - 0.75 = 1.5 lbs

    We have calculated the weight of 3 cups of water. To calculate the weight of one cup we simply divide the result by 3.

    1.5 / 3 = 0.5 lbs (1 cup)

    Finally, we have the information needed for the equation. It wiil be the weight of the empty jug plus the weight of one cup of water multiplied by x.

    jugs weight (y) = 0.75 + 0.5 x

    Feel free to ask for more if it's necessary or if you did not understand something
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An empty 5 gallon water jug weighs 0.75 lbs. With 3 cups of water inside, the jug weighs 2.25 lbs. What equation models the jug's weight y ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers