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12 June, 00:53

Find the magnitude and direction angle for the vector v=6cos137degrees i+6sin137degrees j.

A.) 6,137 degrees

B.) 6,43 degrees

C.) 6squareroot of 2, 43 degrees

D.) 6squareroot of 2, 137 degrees

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Answers (1)
  1. 12 June, 00:55
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    The vector in its generic form is given by:

    v = lvl * (cos (theta) i + sin (theta) j)

    Where,

    lvl: magnitude of the vector

    theta: direction angle

    We have the following vector:

    v = 6cos137degrees i + 6sin137degrees j.

    Rewriting:

    v = 6 (cos137degrees i + sin137degrees j)

    Thus,

    lvl = 6

    theta = 137 degrees

    Answer:

    The magnitude and direction angle for the vector are:

    A.) 6,137 degrees
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