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21 April, 21:57

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green, and 4 are yellow. What is the probability of choosing one candy that is not green?

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Answers (2)
  1. 21 April, 22:09
    0
    92 out of 100

    Step-by-step explanation:

    Add all of the numbers up. That equals 100. Add everything up except the green. That's 92. So 92/100
  2. 21 April, 22:25
    0
    21/25

    Step-by-step explanation:

    First we need to find the probability of getting a candy that is green

    P (green) = green/total

    = 8/50

    = 4/25

    We know that

    P (not green) = 1 - P (green)

    because these are the only two events that can happen

    Either the candy is green or it is not green.

    P (not green) = 1 - 4/25

    = 25/25 - 4/25

    = 21/25
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