Suppose a triangle has sides a, b, and c let theta be the angle opposite the side of length a. If cos theta < 0 what must be true?

a - b^2+c^2>a^2

b - a^2+b^2=c^2

c - b^2+c^2 d - a^2+b^2>c^2

Question

Yasmine Montoya

Mathematics

4 December, 21:28

Suppose a triangle has sides a, b, and c let theta be the angle opposite the side of length a. If cos theta < 0 what must be true?

a - b^2+c^2>a^2

b - a^2+b^2=c^2

c - b^2+c^2 d - a^2+b^2>c^2

+1

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Leia Aguirre · Answer 1

Suppose a triangle has sides a, b, and c let theta be the angle opposite the side of length a. If cos theta < 0 The statement that is true is b^2+c^2>a^2. The answer is letter A.

Suppose a triangle has sides a, b, and c let theta be the angle opposite the side of length a. If cos theta < 0 what must be true?a - b^2+c^2>a^2b - a^2+b^2=c^2c - b^2+c^2 d - a^2+b^2>c^2

Suppose a triangle has sides a, b, and c let theta be the angle opposite the side of length a. If cos theta < 0 what must be true?

a - b^2+c^2>a^2

b - a^2+b^2=c^2

c - b^2+c^2 d - a^2+b^2>c^2