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Oscar Randall
Mathematics
27 September, 14:30
Factor. 3n4+21n3+27n2
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Douglas Boyer
27 September, 14:34
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To factor out the expression we look for number which is divisible by every term in our case it is 3n^2:
3n^4+21n^3+27n^2
we first begin by factoring out 3n^2, this will give us;
3n^2 (n^2+7n+9)
hence, since we cannot factorize the quadratic expression the answer remains to be:
3n^2 (n^2+7n+9)
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