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15 December, 15:25

Find The vertex of this parabola y=4x^2+8x+1?

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  1. 15 December, 15:38
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    Y=4x^2+8x+1

    =4 (x^2+2x) + 1

    =4 (x+1) ^2 - 3

    The vertex is (-1, - 3)
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