What is the vertex and transformation of f (x) = - 2 (x+3) ^2

I am not sure about the transformation but i think the vertex is (-3,2)

If the original function is f (x) = x^2

to movve a function to the right c units, subtract c from every x

to vertically shrink a function by a factor of p, multiply whole function by p

to flip it over the x axis, multiply whole funtion by - 1

so

f (x) = x^2

added 3 to every x (moved - 3 units to right)

f (x) = (x+3) ^2

vertically shrunk by a factor of 2

f (x) = 2 (x+3) ^2

flipped about the x axis (times - 1 whole function)

f (x) = - 2 (x+3) ^2

transformations is vertically compressed by a factor of 2 and moved to the left 3 units and reflected about the x axis

the vertex:

in form

f (x) = a (x-h) ^2+k

the vertex is (h, k)

f (x) = - 2 (x - (-3)) ^2+0

vertex is (-3,0)