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20 October, 01:11

What is the vertex and transformation of f (x) = - 2 (x+3) ^2

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Answers (2)
  1. 20 October, 01:18
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    I am not sure about the transformation but i think the vertex is (-3,2)
  2. 20 October, 01:34
    0
    If the original function is f (x) = x^2

    to movve a function to the right c units, subtract c from every x

    to vertically shrink a function by a factor of p, multiply whole function by p

    to flip it over the x axis, multiply whole funtion by - 1

    so

    f (x) = x^2

    added 3 to every x (moved - 3 units to right)

    f (x) = (x+3) ^2

    vertically shrunk by a factor of 2

    f (x) = 2 (x+3) ^2

    flipped about the x axis (times - 1 whole function)

    f (x) = - 2 (x+3) ^2

    transformations is vertically compressed by a factor of 2 and moved to the left 3 units and reflected about the x axis

    the vertex:

    in form

    f (x) = a (x-h) ^2+k

    the vertex is (h, k)

    f (x) = - 2 (x - (-3)) ^2+0

    vertex is (-3,0)
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