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28 June, 23:27

what is the cost of a new trampoline cover that needs to cover a trampoline with a diameter of 8 feet if the material cost 6.75 per square foot?

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Answers (2)
  1. 28 June, 23:41
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    Answer: The cost of the new trampoline cover is $339.29

    Step-by-step explanation:

    Hi, we have to calculate the area of the trampoline cover.

    Since it has a circle form with a 8 ft diameter.

    Area of a circle = π r^2

    Since the radius (r) is equal to the diameter (d) divided by 2

    R = d/2 = 8/2 = 4

    Replacing in the formula:

    A = π 4^2 = 50.26 square ft

    Since the material cost 6.75 per square foot

    Cost = 6.75 x 50.26 = $339.29
  2. 28 June, 23:52
    0
    Answer: The cost of the trampoline cover would be $339.12

    Step-by-step explanation: The radius of the trampoline is 4 feet (Diameter divided by 2 equals radius).

    The trampoline cover will effectively cover the entire area of the trampoline and the area is given as

    Area of circle = πr²

    Area of circle = 3.14 x 4²

    Area of circle = 3.14 x 16

    Area of circle = 50.24 square foot

    However the material costs $6.75 per square foot, which means the total cost of the trampoline cover would be derived as

    Total area x cost per square foot = cost of trampoline cover

    50.24 x 6.75 = Cost of trampoline cover

    $339.12 = Cost of trampoline cover
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