Out of the students in a class, 60% are geniuses, 70% love chocolate, and 40% fall into both categories. Determine the probability that a randomly selected student is neither a genius nor a chocolate lover.

0.1

Step-by-step explanation:

Let G represent geniuses

Let C represent chocolate

P (G) = 60% = 0.60

P (C) = 70% = 0.70

P (G and C) = 40% = 0.40

P (G and C) = P (G) + P (C) - P (G or C)

0.4 = 0.6 + 0.7 - P (G or C)

0.4 = 1.3 - P (G or C)

P (G or C) = 1.3 - 0.4

= 0.9

P (student is neither a genius or chocolate lover) = 1 - P (G or C)

= 1 - 0.9

= 0.1