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20 August, 18:24

Is x-5 a factor of p (x) = x^3-6x^2-x+30

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  1. 20 August, 18:54
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    yes

    Step-by-step explanation:

    Dividing : x3-6x2-x+30

    ("Dividend")

    By : x-5 ("Divisor")

    dividend x3 - 6x2 - x + 30

    - divisor * x2 x3 - 5x2

    remainder - x2 - x + 30

    - divisor * - x1 - x2 + 5x

    remainder - 6x + 30

    - divisor * - 6x0 - 6x + 30

    remainder 0

    Quotient : x2-x-6 Remainder: 0
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