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8 November, 10:01

Using the discriminant, determine the number of real solutions. - 4x^2+20x-25=0

A) no real solutions

B) one real solution

C) two real solutions

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Answers (1)
  1. 8 November, 10:19
    0
    -4x² + 20x - 25 = 0

    The discriminant Δ = b² - 4. a. c, where a = - 4; b = 20 & c = - 25

    Then Δ = (20) ² - 4 (-4) (-25)

    Δ = 0, since the discriminant = 0, we have one real solution (answer B)

    For more info about Δ, If:

    Δ > 0, then there are 2 real solutions, x' and x"

    Δ = 0, then there are 2 equal real solutions, x' = x"

    Δ < 0, then there are no solutions, or 2 imaginary values of x' and x"
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