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A firefighter wishes to aim his fire hose such that the stream of water goes directly into the second story which has caught on fire. the second story window is at a height of 20 m above the ground. water exits the fire hose at a speed 25 m/s and the firefighter aims it at an angle 60°. how far from the building must he stand?

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  1. 4 June, 23:54
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    Since the water stream forms an arc, this can be solved using the derived equation for projectile motions. In particular, we use the equation for the trajectory of a projectile:

    y = xtanθ + gx/2v²cosθ

    where

    y = 20 m

    θ = 60°

    g = 9.81 m/s²

    v = 25 m/s

    Substituting the values:

    20 = xtan60° + (9.81) x/2 (25) ²cos60°

    Solving for x,

    x = 11.44 m

    Therefore, the firefighter must be 11.44 m away from the base of the building.
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