Wind resistance is jointly proportional to velocity and surface area of the object. If an object is traveling 57 mph and has a surface area of 31 square feet it will experience a wind resistance of 397.575 Newtons. How fast must an object be moving to experience a wind resistance of 228.375 Newtons if it has a surface area of 35 square feet?

Question

Freddy Castaneda

Mathematics

8 December, 07:27

Wind resistance is jointly proportional to velocity and surface area of the object. If an object is traveling 57 mph and has a surface area of 31 square feet it will experience a wind resistance of 397.575 Newtons. How fast must an object be moving to experience a wind resistance of 228.375 Newtons if it has a surface area of 35 square feet?

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Answers (1)

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Branden Webster · Answer 1

Answer

= 29 mph

Explanation

The first step is to calculate the constant of proportionality.

R ∝ KVA

R = KVA Where R is resistance, K is constant, V is velocity and A is surface area.

397.575 = K * 57 * 31

k = 397.575//1,767

= 0.225

The equation now is;

R = 0.225VA

228.375 = 0.225 * V * 35

V = 228.375/7.875

= 29 mph