What are the solutions? 16x^2+9=0

Answer: + 3/4 i and - 3/4 i

Step-by-step explanation:

16x^2 + 9 = 0

subtract 9 from bothside

16x^2 + 9 - 9 = 0 - 9

16x^2 = - 9

Divide bothside by 16

16x^2 / 16 = - 9/16

x^2 = - 9/16

take the square root of bothside

x = √ - 9/16

x = √ 9/16 * √-1

x = ± 3 / 4 i

Note : √ - 1 = i

Therefore; x = 3i/4 and - 3i/4 i

Step-by-step explanation:

x1

= - 0 - √ 02 - 4*16*9

2*16

= 0 - 24 * √ 1 i

32

= - 0.75i

x2

= - 0 + √ 02 - 4*16*9

2*16

= 0 + 24 * √ 1 i

32

= 0.75i